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12n-n^2=36
We move all terms to the left:
12n-n^2-(36)=0
We add all the numbers together, and all the variables
-1n^2+12n-36=0
a = -1; b = 12; c = -36;
Δ = b2-4ac
Δ = 122-4·(-1)·(-36)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$n=\frac{-b}{2a}=\frac{-12}{-2}=+6$
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